If a part on a production line is present in an inspection area, a sensor detects it with probability 0.99. If a part is not present, the sensor generates a false alarm with probability 0.02. Assume that the probability of a part being present is 0.1.
a) What is the probability of seeing a false alarm?
b) What is the probability of having a missed detection?
Ans:
P(alarm/part present)=0.99
P(alarm/part not present)=0.02
P(part present)=0.1
a)
P(seeing a false alarm)=P(alarm and part not present)
=P(alarm/part not present)*P(part not present)
=0.02*(1-0.1)
=0.018
b)
P(alarm)=P(alarm/part present)*P(part present)+P(alarm/part not present)*P(part not present)
=0.99*0.1+0.02*(1-0.1)
=0.117
P(do not alarm)=1-0.117=0.883
P(missed detection)=P(part present/do not alarm)
=P(do not alarm/part present)*P(part present)/P(do not alarm)
=(1-0.99)*0.1/0.883
=0.00113
Get Answers For Free
Most questions answered within 1 hours.