Question

J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet. Random samples of sales receipts were studied for mail-order sales and internet sales, with the total purchase being recorded for each sale. A random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $83.10 with a standard deviation of $25.75. A random sample of 12 sales receipts for internet sales results in a mean sale amount of $78.10 with a standard deviation of $16.25. Using this data, find the 95% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases. Assume that the population variances are not equal and that the two populations are normally distributed.

Step 1 of 3:

Find the point estimate that should be used in constructing the confidence interval.

Step 2 of 3:

Find the margin of error to be used in constructing the confidence interval. Round your answer to six decimal places.

Step 3 of 3:

Construct the 95% confidence interval. Round your answers to two decimal places.

Answer #1

i am denoting the two sample by 1 and 2 respectively.

*given data
are:-*

.

1).**the point
estimate that should be used in constructing the confidence
interval is:-**

2).degrees of freedom :-

*t critical value for
df=25,alpha= 0.05, both tailed test be:-*

[ using t distribution table]

**the margin of error
to be used in constructing the confidence interval
is:-**

3).**the 95%
confidence interval is :-**

*** if you have any doubt regarding the problem please write it
in the comment box.if you are satisfied please give me a
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