According to a 2009 Reader's Digest article, people throw away
approximately 10% of what they buy at the grocery store. Assume
this is the true proportion and you plan to randomly survey 101
grocery shoppers to investigate their behavior. What is the
probability that the sample proportion exceeds 0.2?
Answer = (Enter your answer as a number accurate to 4
decimal places.)
Solution-
According to question,
People throw away approximately 10% of what they buy at the grocery store.
So, Probability of throwing the grocery = 0.1
Random survey of number grocer shoppers to investigate their behavior=101
So, n=101
We know that for the population proportion, test statistics is
Here, p^ =0.2
So, on putting the values,we get
Or
Or
Or
Or
Now, from the standard normal distribution table
P(z <3.35)==0.9996
Now, the probability that the sample proportion exceeds 0.2
P(p > 0.2)
= P(z >3.35)
= 1- P(z <3.35)
= 1- 0.9996
=0.0004
Hence, Probability that the sample proportion exceeds 0.2 is 0.0004
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