Question

Given a periodic sample of 30 from a population of 500 with a sample average of...

Given a periodic sample of 30 from a population of 500 with a sample average of 12.125 and sample standard deviation of 0.125, what 90% confidence interval for the true average of the entire population?

What is the 90% confidence interval for the true average for a population if 12 samples were measured with and average of 1.257 and a standard deviation of 0.034?

Given 30 samples which have an average length of 15.427 with a standard deviation of 0.0035, what is the %Probability of acceptance for the entire population if the desired tolerance is 15.425±0.010

What is the 90% confidence interval for the true mean of the previous problem, average length of 15.427 with a standard deviation of 0.0035?

If the previous problem had only 8 samples, average length of 15.427 with a standard deviation of 0.0035, what is the %Probability of acceptance for the entire population if the desired tolerance is 15.425±0.010, hint: you must interpolate between level of significance values in the t-table

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A sample of size 30 is taken from the population of morel mushrooms and used to...
A sample of size 30 is taken from the population of morel mushrooms and used to calculate an average height x ¯ = 4.6 centimeters.. Suppose the sample standard deviation is calculated to be s =0.5. What is the margin of error for a 90% confidence interval? Round your answer to 3 decimal places.
​​​​​​A confidence interval is desired for the true average sale volume. Assume that the population standard...
​​​​​​A confidence interval is desired for the true average sale volume. Assume that the population standard deviation is known to be 3. How large a random sample is needed to construct a 99% interval for the true average sale volume with a margin of error equal to 1?
A water supplying company wishes to estimate the average amount that private customers pay per month....
A water supplying company wishes to estimate the average amount that private customers pay per month. A random sample of 25  customers' bills during a given month produced a sample mean of $30, and a sample standard deviation of $5. (So, the current problem differs from the previous. In the previous problem, $5 presented the standard deviation for the whole population, while in these problem, $5 is the standard deviation on; only for a sample of 25 customers.)   a) Without any...
A random sample of 30 Suffolk University employees had an average commute length of 11.7 miles,...
A random sample of 30 Suffolk University employees had an average commute length of 11.7 miles, with a standard deviation of 8.5 miles. What is the 90% ​confidence interval ​for the ​mean​ commute length of all Suffolk employees? Use 4 non-zero decimal places in your calculations. (a) Find the tα/2 , df (b) Find σx (c) Find the margin of error (MoE) and construct the confidence interval
A sample of 36 sheets of metal from a large normal population has a mean thickness...
A sample of 36 sheets of metal from a large normal population has a mean thickness of 30 mm. We know from previous quality control testing that the population standard deviation is 3.3 mm. Develop a 95% confidence interval for the true mean for the population.
Problem 9-22 (modified). A quality control inspector accepts shipments of 500 precision .5" steel rods if...
Problem 9-22 (modified). A quality control inspector accepts shipments of 500 precision .5" steel rods if the mean diameter of a sample of 81 falls between .4995" and .5005". Previous evaluations have established that the standard deviation for individual rod diameters is .003". What is the probability the inspector will accept an out-of-tolerance shipment having mu=.5003? (Note: we aren't told the tolerance, but for simplicity assume that it is .0002 so that mu=.5003 is out-of-tolerance. The acceptance standard of between...
1)Given a sample mean is82, the sample size is 100and the population standard deviation is 20....
1)Given a sample mean is82, the sample size is 100and the population standard deviation is 20. Calculate the margin of error to 2 decimalsfor a 90% confidence level. 2)Given a sample mean is 82, the sample size is 100 and the population standard deviation is 20. Calculate the confidence interval for 90% confidence level. What is the lower limit value to 2 decimals? 3)Given a sample mean is 82, the sample size is 100 and the population standard deviation is...
A simple random sample of 100 items from a population with a population standard deviation of...
A simple random sample of 100 items from a population with a population standard deviation of 9 resulted in a sample mean of 42. 1. Determine a 90% confidence interval for the population mean. 2. Determine a 95% confidence interval for the population mean. 3. What happened to the width of the confidence interval as the level of confidence increased from 90% to 95%?
1. A sample of 35 circuits from a large normal population has a mean resistance of...
1. A sample of 35 circuits from a large normal population has a mean resistance of 2.35 ohms. We know from past testing that the a) population standard deviation is 0.45 ohms. b) population standard deviation is 0.48 ohms. c) population standard deviation is 0.43 ohms. d) population standard deviation is 0.46 ohms. Determine a 95% confidence interval for the true mean resistance of the population 2. a)Arandomsampleofn=20has x=45ands=8. b)Arandomsampleofn=22has x=48ands=9. c)Arandomsampleofn=20has x=45ands=8. d)Arandomsampleofn=22has x=48ands=9. Form a 95% confidence interval...
1)Construct a 95% confidence interval estimate for the population mean given that s =30 , and...
1)Construct a 95% confidence interval estimate for the population mean given that s =30 , and n = 20. 2) A random sample of 81 workers at a company showed that they work an average of 100 hours per month with a standard deviation of 27 hours. At 95% confidence, how many more workers need to be included in the sample to provide a confidence interval with length 4 (i.e., the margin of error being 2)?
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT