Suppose that we have the data from 10 subjects and they reported their ages as the following: 19, 24, 31, 31, 54, 34, 62, 22, 45, 27. What is the standard deviation of this sample? (Round to two decimal places)
Answer)
19, 24, 31, 31, 54, 34, 62, 22, 45, 27
First we need to find the sample mean
Sample mean = (sum of the observations)/(number of observations)
Sample mean = (19+24+.....)/(10) = 34.9
Now we need to subtract this mean from each and every observation and then we need to take the square and add all the results
= (19-34.9)^2 + (24-34.9)^2....
= 1832.9
Now we need to divide 1832.9 by n-1 that is by 9
And take the square root
S.d = √{1832.9/9} = 14.2708 ~ 14.27
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