A random sample of size 20 from a normal population has a mean of x-bar = 62.8 and s = 3.55. If you were to test the following hypothesis at the .05 level of significance the rejection region would best be defines as
H0: µ = 60
H0: µ ╪ 60
t > 2.093 or t < -2.093
t > 1.729 or t < -1.729
t > 1.725 or t < -1.725
t > 2.086 or t < -2.086
Solution :
The null and alternative hypothesis is ,
H0 : = 60
Ha : 60
= 62.8
s = 3.55
n = 20
degrees of freedom = n - 1 = 20 - 1 = 19
This is the two tailed test
= 0.05
/2 = 0.025
t/2,df = t0.025,19 = 2.093
correct option is = t > 2.093 or t < -2.093
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