The dean of a college is interested in the proportion of graduates from his college who have a job offer on graduation day. He is particularly interested in seeing if there is a difference in this proportion for accounting and economics majors. In a random sample of 200 of each type of major at graduation, he found that 70 accounting majors and 60 economics majors had job offers. Assume pooled estimate of the population proportion and a level of significance (α) of 0.05.
By MINITAB we get the following result
Sample X N Sample p
1 70 200 0.350000
2 60 200 0.300000
Difference = p (1) - p (2)
Estimate for difference: 0.05
95% CI for difference: (-0.0416689, 0.141669)
Test for difference = 0 (vs not = 0): Z = 1.07 P-Value = 0.286
Since, p-value>0.05, we donot reject the null hypothesis, i.e., we can not have enough evidence to conclude that the proportions are different
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