A poll of 2,133 randomly selected adults showed that 94% of them own cell phones. The technology display below results from a test of the claim that 92% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.01
significance level to complete parts (a) through (e).
Test
of
pequals |
0.92vs
pnot equals
0.92
Sample |
X |
N |
Sample p |
95% CI |
Z-Value |
P-Value |
---|---|---|---|---|---|---|
1 |
1996 |
2 comma 133
0.935771
(0.922098,0.949444
) |
2.68 |
0.007
a. Is the test two-tailed, left-tailed, or right-tailed?
Left-tailed test
Two-tailed test
Right tailed test
b. What is the test statistic?
The test statistic is
.(Round to two decimal places as needed.)
c. What is the P-value?
The P-value is
nothing
.(Round to three decimal places as needed.)
d. What is the null hypothesis and what do you conclude about it?
Identify the null hypothesis.
A.
Upper H 0 : p less than 0.92
B.
Upper H 0 : p equals 0.92
C.
Upper H 0 : p not equals 0.92
D.
Upper H 0 : p greater than 0.92
Choose the correct answer below.
A.
Reject
the null hypothesis because the P-value is
less than or equal to
the significance level,
alpha
.
B.
Fail to reject
the null hypothesis because the P-value is
less than or equal to
the significance level,
alpha
.
C.
Reject the null hypothesis because the P-value is
greater than
the significance level,
alpha
.
D.
Fail to reject
the null hypothesis because the P-value is
greater than
the significance level,
alpha
.
e. What is the final conclusion?
A.
There
is not
sufficient evidence to warrant rejection of the claim that
92
%
of adults own a cell phone.
B.
There
is not
sufficient evidence to support the claim that 92% of adults own a cell phone.
C.There is sufficient evidence to support the claim that 92% of adults own a cell phone.
D.There is sufficient evidence to warrant rejection of the claim that 92%
of adults own a cell phone.
Click to select your answer(s).
Solution :
a) This is the two tailed test .
The null and alternative hypothesis is
H0 : p = 0.92
Ha : p 0.92
= 0.94
n = 2133
P0 = 0.92
1 - P0 = 1 -0.92 = 0.08
b) Test statistic = z
= - P0 / [P0 * (1 - P0 ) / n]
=0.94 -0.92 / [0.92*(0.08) /2133 ]
= 3.40
c) P(z >3.40 ) = 1 - P(z <3.40 ) = 0.0003
P-value = 0.000
= 0.01
0.0003 < 0.01
Reject
d)B.Upper H 0 : p equals 0.92
A.Reject the null hypothesis because the P-value is
less than or equal to
the significance level,
alpha
e) C.There is sufficient evidence to support the claim that 92% of adults own a cell phone.
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