Question

In a survey of 619 males ages 18-64, 395 say they have gone to the dentist...

In a survey of 619 males ages 18-64, 395 say they have gone to the dentist in the past year. Construct 90% and 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals.

The 90% confidence interval for the population proportion p is ( __ _, ___ ). (Round to three decimal places as needed.)

The 95% confidence interval for the population proportion p is (___ , ___ ). (Round to three decimal places as needed.)

Interpret your results of both confidence intervals. Select answer

A. With the given confidence, it can be said that the population proportion of males ages 18-64 who say they have gone to the dentist in the past year is not between the endpoints of the given confidence interval.

B. With the given confidence, it can be said that the population proportion of males ages 18-64 who say they have gone to the dentist in the past year is between the endpoints of the given confidence interval.

C. With the given confidence, it can be said that the sample proportion of males ages 18-64 who say they have gone to the dentist in the past year is between the endpoints of the given confidence interval. Which interval is wider?

Homework Answers

Answer #1

The statistical software output for this problem is:

One sample proportion summary confidence interval:
p : Proportion of successes
Method: Standard-Wald

90% confidence interval results:

Proportion Count Total Sample Prop. Std. Err. L. Limit U. Limit
p 395 619 0.63812601 0.019314638 0.60635626 0.66989576

95% confidence interval results:

Proportion Count Total Sample Prop. Std. Err. L. Limit U. Limit
p 395 619 0.63812601 0.019314638 0.60027001 0.67598201

Hence,

90% confidence interval: (0.606, 0.670)

95% confidence interval: (0.600, 0.676)

Interpretation: Option B is correct.

95% confidence interval is wider.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
In a survey of 607 males ages​ 18-64, 393 say they have gone to the dentist...
In a survey of 607 males ages​ 18-64, 393 say they have gone to the dentist in the past year. Construct​ 90% and​ 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals. If​ convenient, use technology to construct the confidence intervals. The​ 90% confidence interval for the population proportion p is ​(______,______​). ​(Round to three decimal places as​ needed.) The​ 95% confidence interval for the population proportion p is ​(______,_______). ​(Round...
in a survey of 633 males ages​ 18-64, 393 say they have gone to the dentist...
in a survey of 633 males ages​ 18-64, 393 say they have gone to the dentist in the past year. Construct​ 90% and​ 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals. If​ convenient, use technology to construct the confidence intervals.
In a survey of 609609 males ages​ 18-64, 397397 say they have gone to the dentist...
In a survey of 609609 males ages​ 18-64, 397397 say they have gone to the dentist in the past year. Construct​ 90% and​ 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals. If​ convenient, use technology to construct the confidence intervals. The​ 90% confidence interval for the population proportion p is ​(nothing​,nothing​). ​(Round to three decimal places as​ needed.)
Explain how to solve this please and thanks Construct 90% and 95% confidence intervals for the...
Explain how to solve this please and thanks Construct 90% and 95% confidence intervals for the population proportion. In a survey of 674 US males ages 18 to 64; 396 say they have gone to the dentist in the past year
In a survey of 2437 adults in a recent​ year, 1302 say they have made a...
In a survey of 2437 adults in a recent​ year, 1302 say they have made a New​ Year's resolution. Construct​ 90% and​ 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals. The​ 90% confidence interval for the population proportion p is left parenthesis nothing comma nothing right parenthesis,. ​(Round to three decimal places as​ needed.) The​ 95% confidence interval for the population proportion p is left parenthesis nothing comma nothing right...
In a survey of 2674 adults, 1470 say they have started paying bills online in the...
In a survey of 2674 adults, 1470 say they have started paying bills online in the last year. Construct a​ 99% confidence interval for the population proportion. Interpret the results. 1) The​ 90% confidence interval for the population proportion p is (_,_) (Round to three decimal places as needed.) Interpret your results. Choose the correct answer below. A. With​ 99% confidence, it can be said that the population proportion of adults who say they have started paying bills online in...
In a survey of 3398 adults, 1487 say they have started paying bills online in the...
In a survey of 3398 adults, 1487 say they have started paying bills online in the last year. Construct a 99% confidence interval for the population proportion. Interpret the results. A 99% confidence interval for the population proportion is (___,___). (Round to three decimal places as needed.) Interpret your results. Choose the correct answer below. A. With 99% confidence, it can be said that the population proportion of adults who say they have started paying bills online in the last...
In a survey of 3123 ​adults, 1492 say they have started paying bills online in the...
In a survey of 3123 ​adults, 1492 say they have started paying bills online in the last year. 1. Construct a​ 99% confidence interval for the population proportion. ______- 2. Interpret the results. (multiple choice) A. The endpoints of the given confidence interval show that adults pay bills online​ 99% of the time. B.With​ 99% confidence, it can be said that the population proportion of adults who say they have started paying bills online in the last year is between...
In a survey of 3125 adults,1415 say they have started paying bills online in the last...
In a survey of 3125 adults,1415 say they have started paying bills online in the last year. Construct a 99% confidence interval for the population proportion. Interpret the results. A. 99% confidence interval for the population proportion is______ (Round to three decimal places as needed.) Interpret your results. Choose the correct answer below. A. With 99% confidence, it can be said that the population proportion of adults who say they have started paying bills online in the last year is...
In a survey of 2667 ?adults, 1422 say they have started paying bills online in the...
In a survey of 2667 ?adults, 1422 say they have started paying bills online in the last year. Construct a? 99% confidence interval for the population proportion. Interpret the results. A? 99% confidence interval for the population proportion is left parenthesis nothing comma nothing right parenthesis . ?(Round to three decimal places as? needed.) Interpret your results. Choose the correct answer below. A. The endpoints of the given confidence interval show that adults pay bills online? 99% of the time....
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT