Diagnostic tests of medical conditions can have several types of results. The test result can be positive or negative, whether or not a patient has the condition. A positive test (+) indicates that the patient has the condition. A negative test (−) indicates that the patient does not have the condition. Remember, a positive test does not prove the patient has the condition. Additional medical work may be required. Consider a random sample of 200 patients, some of whom have a medical condition and some of whom do not. Results of a new diagnostic test for a condition are shown.
Condition Present | Condition Absent | Row Total | |
Test Result + | 100 | 30 | 130 |
Test Result − | 15 | 55 | 70 |
Column Total | 115 | 85 | 200 |
Assume the sample is representative of the entire population. For a person selected at random, compute the following probabilities. (Enter your answers as fractions.)
(a) P(+ | condition present);
this is known as the sensitivity of a test.
(b) P(− | condition present); this
is known as the false-negative rate.
(c) P(− | condition absent); this
is known as the specificity of a test.
(d) P(+ | condition absent); this
is known as the false-positive rate.
(e) P(condition present
and +); this is the predictive value of the
test.
(f) P(condition present
and −).
(a) P(+ | condition present); this is known as the sensitivity of a test.
Answer: =P(+ and condition present)/P(condition present)
=(100/200)/(115/200)=100/115
similarly
(b) P(− | condition present); this is known as the false-negative rate.
=(15/200)/(115/200)=100/115
Answer: =15/115
(c) P(− | condition absent); this is known as the specificity of a test.
=(55/200)/(85/200)=55/85
Answer: =55/85
(d) P(+ | condition absent); this is known as the false-positive rate.
=(30/200)/(85/200)=30/85
Answer: =30/85
(e) P(condition present and +); this is the predictive value of the test.
Answer 100/200
(f) P(condition present and −).
Answer: 15/200
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