scores on an aptitude test are normally distributed with a means of 400 and a standard deviation of 60. explain how you would find any given percentile
We are given that scores are normally distributed.
We are given
Mean = 400
SD = 60
The formula for finding any percentile X is given as below:
X = Mean + Z*SD
X = 400 + Z*60
So, you need to find the Z value for the given percentile by using z-table or excel; and then you can find required percentile by using above formula.
Suppose, you want to find the 75th percentile; then corresponding z value by using z-table or excel is given as 0.67449.
So, required percentile is given as below:
X = 400 + Z*60
X = 400 + 0.67449*60
X = 440.4694
75th percentile = 440.4694
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