20 Items were randomly selected from a large inventory. If 10% of the items in the inventory are made in Asia,
n = 20
p = 0.1
It is a binomial distribution.
P(X = x) = nCx * px * (1 - p)n - x
a) P(X = 2) = 20C2 * (0.1)^2 * (0.9)^18 = 0.2852
b) P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2)
= 20C0 * (0.1)^0 * (0.9)^20 + 20C1 * (0.1)^1 * (0.9)^19 + 20C2 * (0.1)^2 * (0.9)^18
= 0.6769
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