Question

You intend to estimate a population mean μμ with the following sample.

66.8

41.4

104.2

83.5

50.6

48.2

44.9

You believe the population is normally distributed. Find the 90% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places (because the sample data are reported accurate to one decimal place).

90% C.I. =

Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.

Answer 1

Since we know that

Since we know that



Sample size (n) = 7
Standard deviation (s) = 23.4479
Confidence interval(in %) = 90

Required confidence interval = (62.8-17.2216, 62.8+17.2216)
Required confidence interval = (45.5784, 80.0216)

Interpretion: We are 90.0% confident that the true mean of the population lie between the interval 45.58 and 80.02.

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