The distribution of scores on a standardized aptitude test is approximately normal with a mean of 500 and a standard deviation of 95 What is the minimum score needed to be in the top 20%
on this test? Carry your intermediate computations to at least four decimal places, and round your answer to the nearest integer.
Given that, mean (μ) = 500 and standard deviation = 95
We want to find, the value of x such that, P(X > x) = 0.20
Therefore, the minimum score needed to be in the top 20% is 580
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