Sample 1: 1, 2, 3, 4, 5
Sample 2: 2, 4, 6, 8, 10
Use this data to conduct the paired test with a significance level of 0.05. Select the appropriate conclusion below.
-Fail to reject the null hypothesis
-Accept null hypothesis
-Reject null hypothesis
-Unable to reject or fail to reject
Here, we have to use paired t test.
The null and alternative hypotheses for this test are given as below:
H0: µd = 0 versus Ha: µd ≠ 0
This is a two tailed test.
We take differnece as sample 2 minus sample 1.
Test statistic for paired t test is given as below:
t = (Dbar - µd)/[Sd/sqrt(n)]
From given data, we have
Dbar = 3
Sd = 1.5811
n = 5
df = n – 1 = 4
α = 0.05
t = (Dbar - µd)/[Sd/sqrt(n)]
t = (3 – 0)/[ 1.5811/sqrt(5)]
t = 4.2426
The p-value by using t-table is given as below:
P-value = 0.0132
P-value < α = 0.05
So, we reject the null hypothesis
Answer:
-Reject null hypothesis
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