A sample mean, sample standard deviation, and sample
size are given. Use the one-mean t-test to perform the required
hypothesis test about the mean, μ, of the population from which the
sample was drawn. Use the critical-value approach.
, , n = 18, H0: μ = 10, Ha: μ < 10, α =
0.01
Group of answer choices
Test statistic: t = -4.43. Critical value: t = -2.33. Reject H0. There is sufficient evidence to support the claim that the mean is less than
Test statistic: t = -4.43. Critical value: t = -2.567. Reject H0. There is sufficient evidence to support the claim that the mean is less than
Test statistic: t = -4.43. Critical value: t = -2.33. Do not reject H0. There is not sufficient evidence to support the claim that the mean is less than
Test statistic: t = -4.43. Critical value: t = -2.552. Reject H0. There is sufficient evidence to support the claim that the mean is less than
Solution : -
Given that ,
The null and alternative hypothesis is
H0 : = 10
Ha : < 10
This is the left tailed test .
Test statistic = t = -4.43
n = 18
df = n - 1 = 18 - 1 = 17
= 0.01
t,df = t0.01 , 17 = -2.567
The critical value t = -2.567
-4.43 < -2.567
Test statistic < Critical value
Reject the null hypothesis .
Answer : - Test statistic: t = -4.43. Critical value: t = -2.567. Reject H0. There is sufficient evidence to support the claim that the mean is less than 10 .
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