Question

Consider the experiment of rolling two dice.

​a) What is the probability of obtaining a sum of

ninenine​?

​b) What is the probability of obtaining a sum of

fourfour

or​ less?

​c) What is the probability of obtaining a sum of

tenten

or​ more?

Answer 1

Solution-A:

favourable events for getting nine is

{(4,5),(5,4),(3,6),(6,3)}=4

when 2 dice are rolled total outcomes=6^2=36

P(getting 9)=4/36=1/9

Solution-B:

favorable events of obtaining a sum of four or​ less

(1,1)(1,2),(2,1),(1,3)(3,1)(2,2)=6

when 2 dice are rolled total outcomes=6^2=36

P(getting 4 or less)=6/36=1/6

Solution-c:

favorable events of obtaining a sum of ten or more

(4,6)(6,4)(5,5)(5,6)(6,5)(6,6)=6

when 2 dice are rolled total outcomes=6^2=36

P(getting 10 or more0=6/36=6/36=1/6