A highway department executive claims that the number of fatal accidents which occur in her state does not vary from month to month. The results of a study of 158 fatal accidents were recorded. Is there enough evidence to reject the highway department executive's claim about the distribution of fatal accidents between each month?
Month | Jan | Feb | Mar | Apr | May | Jun | Jul | Aug | Sep | Oct | Nov | Dec |
---|---|---|---|---|---|---|---|---|---|---|---|---|
Fatal Accidents | 17 | 10 | 12 | 19 | 9 | 10 | 10 | 12 | 12 | 18 | 17 | 12 |
H0: the number of fatal accidents which occur in her state does not vary from month to month
H1: Atleast one of the month has different number of fatal accidents
Under H0, the expected number of fatal accident in each month is E =(17+10+....17+12)/12 = 158/12 =13.17
The calculations for Chi square test statistic is
Month | O | E | (O-E)^2/E |
Jan | 17 | 13.17 | 1.114 |
Feb | 10 | 13.17 | 0.763 |
Mar | 12 | 13.17 | 0.104 |
Apr | 19 | 13.17 | 2.581 |
May | 9 | 13.17 | 1.320 |
Jun | 10 | 13.17 | 0.763 |
Jul | 10 | 13.17 | 0.763 |
Aug | 12 | 13.17 | 0.104 |
Sep | 12 | 13.17 | 0.104 |
Oct | 18 | 13.17 | 1.771 |
Nov | 17 | 13.17 | 1.114 |
Dec | 12 | 13.17 | 0.104 |
Total | 158 | 10.605 |
The test statistic is
df = n-1= 11
Signiifcance level = 0.05
At 5% Significance level, the critical value of Chi square is 19.675
Since chi square calculated is less than chi square tabulated, Fail to REject the null hypothesis
Hence, there is not enough evidence to reject the highway department executive's claim about the distribution of fatal accidents between each month.
Get Answers For Free
Most questions answered within 1 hours.