Question

An experiment was conducted for better understanding of the effectiveness of a particular type of drug...

An experiment was conducted for better understanding of the effectiveness of a particular type of drug for reducing bad cholesterol (LDL) level. The purpose of the experiment was to determine whether different dosages used have significant different outcomes in average LDL reduction. Twenty subjects with LDL at around 250 to 300 mg/dL had participated in the study and were randomly divided into four groups. Each group was given a specific level of dosage of the drug each day for one month, with a control group that only provided with placebo. The reduction in LDL was recorded and showed in the following table. Positive number indicates reduction and negative numbers indicates increasing in DLD. Use statistical software to analyze the data and answer the following question.

Control

Light Dosage Level

Medium Dosage Level

Heavy Dosage Level

7

25

73

81

-3

17

60

71

6

22

55

79

5

21

41

60

15

12

36

85

  1. Use statistical software to determine whether the average reduction in LDL differ among people who used different dosages of the drug. Perform a one-way ANOVA F-test and report p-value of the test and draw a conclusion using the level of significance at 5%.

Null hypothesis:

Alternative hypothesis:

Report the value of the F-test statistic =

Report p-value from the F-test and the conclusion:

[Place your software output here.]

  1. Verify the assumptions behind the ANOVA F-test using statistical software and explain your result.

[Place your software output here.]

  1. Use Tukey’s multiple comparison methods to compare all the treatment groups to see where the differences are and also identify homogeneous subsets from these treatment groups.

[Place your software output here.]

Homework Answers

Answer #1

Null hypothesis: H0: The mean reduction in LDL is same for control group and all dosage levels.

Alternative hypothesis: Ha: At least one of the dosage levels or control group have different mean reduction in LDL.

Report the value of the F-test statistic = 51.44

Report p-value from the F-test and the conclusion: p-value = 1.94e-08

Since, p-value is less than 0.05 significance level, we reject null hypothesis H0 and conclude that there is strong evidence that at least one of the dosage levels or control group have different mean reduction in LDL.

By Tukey’s multiple comparison method output, the significant mean differences of reduction in LDL is found in,

Control and Medium Dosage Level ,  Control and Heavy Dosage Level , Light and Medium Dosage Level, Light and Heavy Dosage Level,  Medium and Heavy Dosage Level

The homogeneous subsets are,

Subset 1 - {Control , Light Dosage Level}

Subset 2 - {Medium Dosage Level }

Subset 3 - {Heavy Dosage Level}

On running the below R code, we get the following output.

R code -

# Load the data
LDL <- c(7,-3,6,5,15,
25,17,22,21,12,
73,60,55,41,36,
81,71,79,60,85)
# Create vectors of factors (4 levels) for Dosage levels
Dosage=factor(c(rep(1,5),rep(2,5),rep(3,5),rep(4,5)))


# Fit a regression model on scale for different factors of Dosage levels and run the anova test
summary(model <- aov(LDL ~ Dosage))

# Run the TukeyHSD test
TukeyHSD(model, "Dosage", ordered = TRUE)

> summary(model <- aov(LDL ~ Dosage))
Df Sum Sq Mean Sq F value Pr(>F)
Dosage 3 14891 4964 51.44 1.94e-08 ***
Residuals 16 1544 96   
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

> # Run the TukeyHSD test
> TukeyHSD(model, "Dosage", ordered = TRUE)
Tukey multiple comparisons of means
95% family-wise confidence level
factor levels have been ordered

Fit: aov(formula = LDL ~ Dosage)

$Dosage
diff lwr upr p adj
2-1 13.4 -4.375201 31.1752 0.1777685
3-1 47.0 29.224799 64.7752 0.0000062
4-1 69.2 51.424799 86.9752 0.0000000
3-2 33.6 15.824799 51.3752 0.0003061
4-2 55.8 38.024799 73.5752 0.0000007
4-3 22.2 4.424799 39.9752 0.0121973

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
An experiment was conducted for better understanding of the effectiveness of a particular type of drug...
An experiment was conducted for better understanding of the effectiveness of a particular type of drug for reducing bad cholesterol (LDL) level. The purpose of the experiment was to determine whether different dosages used have significant different outcomes in average LDL reduction. Twenty subjects with LDL at around 250 to 300 mg/dL had participated in the study and were randomly divided into four groups. Each group was given a specific level of dosage of the drug each day for one...
An experiment was done to see the effects of diet and a drug on Type II...
An experiment was done to see the effects of diet and a drug on Type II Diabetes in men in the 50’s. Men in the 50’s who were diagnosed with Type II Diabetes that was under moderate control were randomly selected and randomly assigned to one of 4 treatment groups (8 per group). The groups were a Control group, those given a special diet, those given the drug, and those given the diet and the drug. The control group was...
ANOVA: One Way: A drug trial using different levels of a drug to reduce blood pressure...
ANOVA: One Way: A drug trial using different levels of a drug to reduce blood pressure is conducted to determine the best dosage. A one Way ANOVA is conducted. Claim: The reduction of blood pressure differs by dosage. The results of the study are given in the ANOVA table ANOVA Source of Variation SS df MS F P-value Between Groups 360 4 D E 0.0138 Within Groups A B C Total 660 19          Complete the Table:   A...
An experiment was done to test the effectiveness of a drug that is being considered for...
An experiment was done to test the effectiveness of a drug that is being considered for possible use in the treatment of people who experience chronic anxiety. Fifty people who are chronically anxious are identified through a local health clinic. Twenty-five people are randomly assigned to the experimental group, and they receive the new drug for six weeks. The other 25 people are randomly assigned to the control group, and they receive the commonly used drug for six weeks. After...
An experiment was conducted to test the effect of a new drug on a viral infection....
An experiment was conducted to test the effect of a new drug on a viral infection. After the infection was induced in 100 mice, the mice were randomly split into two groups of 50. The first group, the control group, received no treatment for the infection, and the second group received the drug. After a 30-day period, the proportions of survivors, p?1 and p?2, in the two groups were found to be 0.38 and 0.66, respectively. (a) Is there sufficient...
An experiment was conducted to evaluate the effectiveness of a treatment for tapeworm in the stomachs...
An experiment was conducted to evaluate the effectiveness of a treatment for tapeworm in the stomachs of sheep. A random sample of 24 worm-infected lambs of approximately the same age and health was randomly divided into two groups. Twelve of the lambs were injected with the drug and the remaining twelve were left untreated. After 6 months, the lambs were slaughtered and the following worm counts were recorded. Assume the counts are approximately normally distributed. Drug-treated sheep 18 43 28...
1. ) Suppose a researcher is interested in the effectiveness of a new drug that is...
1. ) Suppose a researcher is interested in the effectiveness of a new drug that is intended to naturally increase hours of sleep for elderly patients experiencing insomnia above 5 hours. Suppose he collects information from a group of 64 patients, and calculates a sample mean of 6.4 hours of sleep and a standard deviation of s=0.8.   Write out your null and alternative hypotheses. Carry out the appropriate statistical test to determine if the new treatment is effective (One sided)?...
A pharmaceutical company performs an experiment to test a new drug against Coronavirus (SARS2-COV).  Their scientists predict...
A pharmaceutical company performs an experiment to test a new drug against Coronavirus (SARS2-COV).  Their scientists predict that this drug will reduce the length of hospital stay for patients, compared to the current standard treatment.  One group of patients (Group A) is given the new drug.  One group of patients (Group B) is given the current standard treatment.   The average length of hospital stays were as follows:  Group A: 6 days.  Group B: 11 days. What is the hypothesis? What is the control? What is the...
ANOVA F test was conducted to test whether the means of four groups are the same...
ANOVA F test was conducted to test whether the means of four groups are the same against at least one group mean is different. The total number of subjects in four samples were 50. The F ratio (test statistics) was 2.45 a) What is the p-value? b) What is your conclusion at 5% significance level? Are all group means the same?
A new drug has been developed that claims to prevent seasickness completely! Design an experiment that...
A new drug has been developed that claims to prevent seasickness completely! Design an experiment that would determine how effective it is. Do you need to define any terms for your experiment (operationally define)? If so, define them here. What is your independent variable? What is your dependent variable? Who are your subjects/participants? How will you select and assign your subjects/participants to a group? What treatment will the experimental group be given? What treatment will the control group be given?...