Question

If 0.243 moles of zinc reacts with excess lead(IV) sulfate, how many grams of zinc sulfate would be produced in the following reaction?

Answer 1

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We know the relation : Pb(SO4)2 + 2 Zn --> 2 ZnSO4 + Pb

Now, lets solve the problem taking hint from above :

Theoretical yield in grams of ZnSO4 from 0.243 moles of Zn and excess Pb(SO4)2 :

= (0.243 moles Zn) x (2 moles ZnSO4 / 2 moles Zn) x (161.44 g ZnSO4 / 1 mole ZnSO4)

= 39.23 grams of ZnSO4 ( Zinc sulfate)

So, 39.23 grams of zinc sulfate would be produced in this reaction