Question

A random sample of 294 adult Canadians was taken, and 196 of them said that they...

A random sample of 294 adult Canadians was taken, and 196 of them said that they always vote in federal general elections. Find a 94% confidence interval for the proportion of adult Canadians who say that they always vote in federal general elections.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A random sample of 299 adult Canadians was taken, and 206 of them said that they...
A random sample of 299 adult Canadians was taken, and 206 of them said that they always vote in federal general elections. Find a 92% confidence interval for the proportion of adult Canadians who say that they always vote in federal general elections.
In a random sample of 250 Winnipeggers, 80 of them said they use transit. A 94%...
In a random sample of 250 Winnipeggers, 80 of them said they use transit. A 94% confidence interval for the true proportion of all Winnipeggers who use transit is: Note: Value of 90%(1.645 and 95%(1.960) is only provided in the table.
In the run-up to the 2016 election, a random sample of 100 people was taken to...
In the run-up to the 2016 election, a random sample of 100 people was taken to determine a confidence interval for the population proportion who would vote in favor of Proposition 61 to legalize marijuana.  The confidence interval was found to be (.402 to .598).   What was the confidence level, (1-alpha)*100%, associated with this confidence interval? 95% 90% We would need to know the number in the sample who said they would vote for Proposition 61.  If we knew this number, we...
3. A random sample of 78 students was interviewed, and 59 students said that they would...
3. A random sample of 78 students was interviewed, and 59 students said that they would vote for Jennifer McNamara as student body president. a.Let p represent the proportion of all students at this college who will vote for Jennifer. Find a point estimate for p. Round your answer to the nearest hundredth. b.Find a 90% confidence interval for p. Round your answer to the nearest hundredth and THEN change them to a percentage. c.Interpret the meaning of the confidence...
The manager of a grocery store has taken a random sample of 196 customers.
The manager of a grocery store has taken a random sample of 196 customers. The average length of time it took these 196 customers to check out was 3 minutes. It is known that the standard deviation of the population of checkout times is 1 minute. The margin of error is 0.140. Find the 95% confidence interval for the true average checkout time (in minutes).A. 1 to 5B. 2.86 to 3.14    C. 2.883 to 3.117D. 2.990 to 3.010
A sample survey asked a random sample of 1498 adult Canadians, “Do you agree or disagree...
A sample survey asked a random sample of 1498 adult Canadians, “Do you agree or disagree that all firearms should be registered?” Of the 1498 people in the sample, 1282 answered either “Agree strongly” or “Agree somewhat.” Assuming this survey can be considered an SRS of all adult Canadians, what is the proportion of all Canadians who agree (as described) that all firearms should be registered? Your solution must include the following parts, in order. Point form is fine. a)...
A random sample of 994 people was taken. 262 of the people in the sample favored...
A random sample of 994 people was taken. 262 of the people in the sample favored Candidate A. Find 90% confidence interval for the true proportion of people who favors Candidate A. Enter in the lower limit of the confidence interval you found.
A random sample of 803 people was taken. 154 of the people in the sample favored...
A random sample of 803 people was taken. 154 of the people in the sample favored Candidate A. Find 90% confidence interval for the true proportion of people who favors Candidate A. Enter in the lower limit of the confidence interval you found.
In a random sample of 200 people, 154 said that they watched educational television. Find the...
In a random sample of 200 people, 154 said that they watched educational television. Find the 90% confidence interval of the true proportion of people who watched educational television. If the television company wanted to publicize the proportion of viewers, do you think it should use the 90% confidence interval?
Educational Television:  In a random sample of 200 people, 154 said that they watched educational television.  Find the...
Educational Television:  In a random sample of 200 people, 154 said that they watched educational television.  Find the 90% confidence interval of the true proportion of people who watched educational television. Then write in a z interval