A person's blood glucose level and diabetes are closely related. Let x be a random variable measured in milligrams of glucose per deciliter (1/10 of a liter) of blood. Suppose that after a 12-hour fast, the random variable x will have a distribution that is approximately normal with mean μ = 89 and standard deviation σ = 25. Note: After 50 years of age, both the mean and standard deviation tend to increase. For an adult (under 50) after a 12-hour fast, find the following probabilities. (Round your answers to four decimal places.)
(a) x is more than 60
(b) x is less than 110
(c) x is between 60 and 110
(d) x is greater than 125 (borderline diabetes starts at
125)
Solution :
Given that ,
mean = = 89
standard deviation = = 25
(a)
P(x > 60) = 1 - P(x < 60)
= 1 - P[(x - ) / < (60 - 89) / 25)
= 1 - P(z < -1.16)
= 1 - 0.123
= 0.8770
Probability = 0.8770
(b)
P(x < 110) = P[(x - ) / < (110 - 89) / 25]
= P(z < 0.84)
= 0.7995
Probability = 0.7995
(c)
P(60 < x < 110) = P[(60 - 89)/ 25) < (x - ) / < (110 - 89) / 25) ]
= P(-1.16 < z < 0.84)
= P(z < 0.84) - P(z < -1.16)
= 0.7995 - 0.123
= 0.6765
Probability = 0.6765
(d)
P(x > 125) = 1 - P(x < 125)
= 1 - P[(x - ) / < (125 - 89) / 25)
= 1 - P(z < 1.44)
= 1 - 0.9251
= 0.0749
Probability = 0.0749
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