How large a sample should be selected to provide a 95% confidence interval with a margin of error of 4? Assume that the population standard deviation is 30 . Round your answer to next whole number.
Solution :
Given that,
standard deviation = = 30
margin of error = E = 4
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.960
Sample size = n = ((Z/2 * ) / E)2
= ((1.960 * 30) / 4 )2
= 216.09
= 216
Sample size = 216
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