Fertilizer: In an agricultural experiment, the effects of two fertilizers on the production of oranges were measured. Ten randomly selected plots of land were treated with fertilizer A, and 7 randomly selected plots were treated with fertilizer B. The number of pounds of harvested fruit was measured from each plot. Following are the results.
Fertilizer A | ||||
464 | 483 | 441 | 491 | 403 |
466 | 448 | 457 | 437 | 516 |
Fertilizer B | ||||
414 |
408 |
398 |
382 |
368 |
393 |
437 |
-Construct a 90% confidence interval for the difference between the mean yields for the two types of fertilizer. Let μ1 denote the mean yield for fertilizer A. Use tables to find the critical value and round the answer to one decimal place.
x1 = | 460.60 | x2 = | 400.00 |
s1 = | 31.56 | s2 = | 22.47 |
n1 = | 10 | n2 = | 7 |
Pooled Variance Sp2=((n1-1)s21+(n2-1)*s22)/(n1+n2-2)= | 799.7600 |
point estimate of difference=x1-x2= | 60.600 | ||
for 90 % CI & 15 df value of t= | 1.753 | ||
margin of error E=t*std error = | 24.4308 | ||
lower bound=mean difference-E= | 36.17 | ||
Upper bound=mean differnce +E= | 85.03 | ||
from above 90% confidence interval for population mean =(36.2 , 85.0) |
Get Answers For Free
Most questions answered within 1 hours.