Question

Construct the indicated confidence interval for the population mean of each data set. If it is...

  1. Construct the indicated confidence interval for the population mean of each data set. If it is possible to construct a confidence interval, justify the distribution you used. If it is not possible, explain why.

***Please provide formulas used, step by step process, and hand write....thank you so much!

  1. In a random sample of 40 patients, the mean waiting time at a dentist’s office was 20 minutes and the standard deviation was 7.5 minutes. Construct a 95% confidence interval for the population mean.
  2. In a random sample of 20 people, the mean tip that they said they would leave after a $30 meal was $3.75 and the standard deviation was $0.25. Construct a 99% confidence interval for the population mean.
  3. In a random sample of 15 cereal boxes, the mean weight was 11.89 ounces. Assume the weights of the cereal boxes are normally distributed and the population standard deviation is 0.05 ounce. Construct a 90% confidence interval for the population mean.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Construct the indicated confidence interval for the population mean of each data set. If it is...
Construct the indicated confidence interval for the population mean of each data set. If it is possible to construct a confidence interval, justify the distribution you used. If it is not possible, explain why. (a) In a random sample of 40 patients, the mean waiting time at a dentist’s office was 20 minutes and the standard deviation was 7.5 minutes. Construct a 95% confidence interval for the population mean. (b) In a random sample of 20 people, the mean tip...
A 99.8% confidence interval for the average weight of a box of cereal if a sample...
A 99.8% confidence interval for the average weight of a box of cereal if a sample of 24 such boxes has an average of 18.08 ounces with a sample deviation of 0.235 ounces. The population of all such weights is normally distributed round to the nearest hundreth of an ounce
Use the standard normal distribution or the​ t-distribution to construct a 99​% confidence interval for the...
Use the standard normal distribution or the​ t-distribution to construct a 99​% confidence interval for the population mean. Justify your decision. If neither distribution can be​ used, explain why. Interpret the results. In a random sample of 13 mortgage​ institutions, the mean interest rate was 3.59​% and the standard deviation was 0.42​%. Assume the interest rates are normally distributed. Select the correct choice below​ and, if​ necessary, fill in any answer boxes to complete your choice. A. The 99​% confidence...
#1.       You are to construct a 99% confidence interval of a normally distributed population; the population...
#1.       You are to construct a 99% confidence interval of a normally distributed population; the population standard deviation is known to be 25. A random sample of size 28 is taken; (i) the sample mean is found to 76 and (ii) the sample standard deviation was found to be 30. Construct the Confidence interval. Clearly name the standard distribution you used (z, or t or F etc.) and show work. (10 points)
Construct a 98% confidence interval for the population mean. Assume the population has a normal distribution....
Construct a 98% confidence interval for the population mean. Assume the population has a normal distribution. A random sample of 40 college students has mean annual earnings of $3200 with a standard deviation of $665.
For the following questions construct the indicated confidence interval for the population mean. Note c =...
For the following questions construct the indicated confidence interval for the population mean. Note c = confidence level, x ̅ which is equal to the sample mean, s = standard deviation, and n = sample size a. c = 0.90, x ̅ = 12.3, s = 1.5, n = 50 b. c = 0.99, x ̅ = 10.5, s = 2.14, n = 45
10 state which type of parameter is to be estimated, then construct the confidence interval 10....
10 state which type of parameter is to be estimated, then construct the confidence interval 10. A simple random sample of size 17 has mean x̄ = 8.44 and standard deviation s = 5.38. The population is normally distributed. Construct a 95% confidence interval for the population standard deviation 10 state which type of parameter is to be estimated, then construct the confidence interval 10. A simple random sample of size 17 has mean x̄ = 8.44 and standard deviation...
1)Construct a 95% confidence interval estimate for the population mean given that s =30 , and...
1)Construct a 95% confidence interval estimate for the population mean given that s =30 , and n = 20. 2) A random sample of 81 workers at a company showed that they work an average of 100 hours per month with a standard deviation of 27 hours. At 95% confidence, how many more workers need to be included in the sample to provide a confidence interval with length 4 (i.e., the margin of error being 2)?
Suppose the time a child spends waiting for the bus at the school bus stop each...
Suppose the time a child spends waiting for the bus at the school bus stop each day is exponentially distributed with a mean of 2 minutes. Suppose waiting times for the bus are independent each day. If we look at two days, determine the probability that the child must wait at most 5 minutes for the bus each of the two days. a. 0.9180 b. 0.8426 c. 0.0821 d. 0.2821 e. 0.4179 A sample of 33 boxes of cereal has...
QUESTION 22 Use your TI83 to find the upper end of the interval requested: A 95%...
QUESTION 22 Use your TI83 to find the upper end of the interval requested: A 95% confidence interval for the average weight of a box of cereal if a sample of 26 such boxes has an average of 17.14 ounces with a sample deviation of 0.228 ounces. The population of all such weights is normally distributed round to the nearest hundreth of an ounce QUESTION 23 Use your TI83 to find the upper end of the interval requested: A 90%...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT