Let the random variable X have the probability distribution listed in the table below. Determine the probability distributions of the random variable left parenthesis Upper X plus 1 right parenthesis squared. k ?Pr(Xequals?k) 0 0.2 1 0.2 2 0.2 3 0.3 4 0.1 Fill in the table for the probability distribution of the variable left parenthesis Upper X plus 1 right parenthesis squared. k ?Pr(left parenthesis Upper X plus 1 right parenthesis squaredequals?k) 1 nothing 4 nothing 9 nothing 16 nothing 25 nothing
Since has the values as 0, 1, 2, 3, 4. So
will have the values as 1, 4, 9, 16, 25
Also , if
So and similarly other probabilities are found. We have the distribution as
1 | 4 | 9 | 16 | 25 | |
0.20 | 0.20 | 0.20 | 0.30 | 0.10 |
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