Question

1.Assume that the helium porosity (in percentage) of coal samples taken from any particular seam is...

1.Assume that the helium porosity (in percentage) of coal samples taken from any particular seam is normally distributed with true standard deviation σ = 0.8. A sample of 13 specimens from the seam produces average porosity 4.6.

The 90% confidence interval for the true average of helium porosity is:
(4.316    ,    4.884)
(4.235    ,    4.965)
(4.205    ,    4.995)

Tries 0/2

What is the minimum sample size required to estimate the true average porosity within 0.1 with 90% confidence?

694 173 174

2.A random sample of 25 adult females is used to calculate a 95% confidence interval for the true mean weight of female adults. Which of the following would reduce the margin of error for the confidence interval? Choose the best answer.
sample size 20
99% confidence and sample size 20
99% confidence level and sample size 30
sample size 30
99% confidence level

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Assume that the helium porosity (in percentage) of coal samples taken from any particular seam is...
Assume that the helium porosity (in percentage) of coal samples taken from any particular seam is normally distributed. How large a sample size is necessary if the width of the 90% interval is to be .20? Sample standard deviation of .65
As humans we consume food. The body extracts good things such as proteins and vitamins and...
As humans we consume food. The body extracts good things such as proteins and vitamins and throws away waste. A typical waste product is uric acid. High levels of uric acid can be an indication of conditions such as gout, kidney disease, and cancer. For females a high level of uric acid is 6 mg/dL or more and for males a high level of uric acid is 7 mg/dL or more. Suppose, over a period of months, an adult female...
A sample of size 30 is taken from the population of morel mushrooms and used to...
A sample of size 30 is taken from the population of morel mushrooms and used to calculate an average height x ¯ = 4.6 centimeters.. Suppose the sample standard deviation is calculated to be s =0.5. What is the margin of error for a 90% confidence interval? Round your answer to 3 decimal places.
The following results are for independent random samples taken from two populations. Sample 1 Sample 2...
The following results are for independent random samples taken from two populations. Sample 1 Sample 2 n1 = 20 n2 = 30 x1 = 22.8 x2 = 20.1 s1 = 2.6 s2 = 4.6 (a) What is the point estimate of the difference between the two population means? (Use x1 − x2. ) (b) What is the degrees of freedom for the t distribution? (Round your answer down to the nearest integer.) (c) At 95% confidence, what is the margin...
The following results are for independent random samples taken from two populations. Sample 1 Sample 2...
The following results are for independent random samples taken from two populations. Sample 1 Sample 2 n1 = 20 n2 = 30 x1 = 22.5 x2 = 20.1 s1 = 2.2 s2 = 4.6 (a) What is the point estimate of the difference between the two population means? (Use x1 − x2. ) (b) What is the degrees of freedom for the t distribution? (Round your answer down to the nearest integer.) (c) At 95% confidence, what is the margin...
The following results are for independent random samples taken from two populations. Sample 1 Sample 2...
The following results are for independent random samples taken from two populations. Sample 1 Sample 2 n1 = 20 n2 = 30 x1 = 22.5 x2 = 20.1 s1 = 2.9 s2 = 4.6 a) What is the point estimate of the difference between the two population means? (Use x1 − x2.) b) What is the degrees of freedom for the t distribution? (Round your answer down to the nearest integer.) c) At 95% confidence, what is the margin of...
1) The weekly oral dose of anabolic steroids was measured on a sample of 20 body...
1) The weekly oral dose of anabolic steroids was measured on a sample of 20 body builders. A 95% confidence interval estimatefortheaverageweeklyoraldoseofanabolicsteroidsobtainedfromtheseresultswas152mgto194 mg. (The margin of error is 21 mg.) Identify which one of the following interpretations is correct. a) 95% of all body builders use between 152 mg and 194 mg of anabolic steroids per week. b) There is a 0.95 probability that the average weekly dose of anabolic steroids used by body builders is between 152 mgand194mg. c)...
1. A sample of 35 circuits from a large normal population has a mean resistance of...
1. A sample of 35 circuits from a large normal population has a mean resistance of 2.35 ohms. We know from past testing that the a) population standard deviation is 0.45 ohms. b) population standard deviation is 0.48 ohms. c) population standard deviation is 0.43 ohms. d) population standard deviation is 0.46 ohms. Determine a 95% confidence interval for the true mean resistance of the population 2. a)Arandomsampleofn=20has x=45ands=8. b)Arandomsampleofn=22has x=48ands=9. c)Arandomsampleofn=20has x=45ands=8. d)Arandomsampleofn=22has x=48ands=9. Form a 95% confidence interval...
1. For a company whose total number of employees is 100, we collect data from 7...
1. For a company whose total number of employees is 100, we collect data from 7 employees ,5.2, 4.1, 10, 6.8, 3.8, 8.0, and 8.3. Using these data, write down the upper bound of the 99% CI for population mean. Assume that these data are from a normal distribution. Please provide answer with 2 decimal points. 2. From a sample of size 250, number of females is 173. What is the point estimate of population proportion? Provide an answer with...
1. A sample size of n = 70 is drawn from a population with proportion p...
1. A sample size of n = 70 is drawn from a population with proportion p = 0.32. Let p̂ be the sample proportion. Find p̂m and p̂s . Round the standard deviation to four decimal places. Find )28.0p̂P ( > . Find )40.0p̂P ( < 2.  On a certain television channel, 20% of the commercials are local advertisers. A sample of 150 commercials is selected. Would it be unusual for more than 26% of the commercials to be local advertisers?...