Question

In a survey of 2800 adults, 1476 say they have started paying bills online in the...

In a survey of 2800 adults, 1476 say they have started paying bills online in the last year.

Construct a​ 99% confidence interval for the population proportion. Interpret the results.

A​ 99% confidence interval for the population proportion is ( ), ( )

​(Round to three decimal places as​ needed.)

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
In a survey of 3398 adults, 1487 say they have started paying bills online in the...
In a survey of 3398 adults, 1487 say they have started paying bills online in the last year. Construct a 99% confidence interval for the population proportion. Interpret the results. A 99% confidence interval for the population proportion is (___,___). (Round to three decimal places as needed.) Interpret your results. Choose the correct answer below. A. With 99% confidence, it can be said that the population proportion of adults who say they have started paying bills online in the last...
In a survey of 2674 adults, 1470 say they have started paying bills online in the...
In a survey of 2674 adults, 1470 say they have started paying bills online in the last year. Construct a​ 99% confidence interval for the population proportion. Interpret the results. 1) The​ 90% confidence interval for the population proportion p is (_,_) (Round to three decimal places as needed.) Interpret your results. Choose the correct answer below. A. With​ 99% confidence, it can be said that the population proportion of adults who say they have started paying bills online in...
In a survey of 3352 ​adults, 1490 say they have started paying bills online in the...
In a survey of 3352 ​adults, 1490 say they have started paying bills online in the last year. Construct a​ 99% confidence interval for the population proportion. Interpret the results. A​ 99% confidence interval for the population proportion is (?,?). (Round to three decimal places as​ needed.)
In a survey of 3125 adults,1415 say they have started paying bills online in the last...
In a survey of 3125 adults,1415 say they have started paying bills online in the last year. Construct a 99% confidence interval for the population proportion. Interpret the results. A. 99% confidence interval for the population proportion is______ (Round to three decimal places as needed.) Interpret your results. Choose the correct answer below. A. With 99% confidence, it can be said that the population proportion of adults who say they have started paying bills online in the last year is...
In a survey of 2667 ?adults, 1422 say they have started paying bills online in the...
In a survey of 2667 ?adults, 1422 say they have started paying bills online in the last year. Construct a? 99% confidence interval for the population proportion. Interpret the results. A? 99% confidence interval for the population proportion is left parenthesis nothing comma nothing right parenthesis . ?(Round to three decimal places as? needed.) Interpret your results. Choose the correct answer below. A. The endpoints of the given confidence interval show that adults pay bills online? 99% of the time....
In a survey of 3287 ​adults, 1459 say they have started paying bills online in the...
In a survey of 3287 ​adults, 1459 say they have started paying bills online in the last year. Construct a​ 99% confidence interval for the population proportion. Interpret the results. A​ 99% confidence interval for the population proportion is left parenthesis nothing comma nothing right parenthesis . ​(Round to three decimal places as​ needed.) Interpret your results. Choose the correct answer below. A. The endpoints of the given confidence interval show that adults pay bills online​ 99% of the time....
In a survey of 3447 ​adults, 1453 say they have started paying bills online in the...
In a survey of 3447 ​adults, 1453 say they have started paying bills online in the last year. Construct a​ 99% confidence interval for the population proportion. Interpret the results. A​ 99% confidence interval for the population proportion is left parenthesis nothing comma nothing right parenthesis . ​(Round to three decimal places as​ needed.) Interpret your results. Choose the correct answer below. A. The endpoints of the given confidence interval show that adults pay bills online​ 99% of the time....
In a survey of 2808 ​adults, 1413 say they have started paying bills online in the...
In a survey of 2808 ​adults, 1413 say they have started paying bills online in the last year. Construct a​ 99% confidence interval for the population proportion. Interpret the results. A​ 99% confidence interval for the population proportion is left parenthesis nothing comma nothing right parenthesis . ​(Round to three decimal places as​ needed.) Interpret your results. Choose the correct answer below. A. With​ 99% confidence, it can be said that the sample proportion of adults who say they have...
1. In a survey of 3230 ​adults, 1418 say they have started paying bills online in...
1. In a survey of 3230 ​adults, 1418 say they have started paying bills online in the last year. Construct a​ 99% confidence interval for the population proportion. Interpret the results. A​ 99% confidence interval for the population proportion is (),() . ​(Round to three decimal places as​ needed.)
In a survey of 34783478 ​adults, 14341434 say they have started paying bills online in the...
In a survey of 34783478 ​adults, 14341434 say they have started paying bills online in the last year. Construct a​ 99% confidence interval for the population proportion. Interpret the results. A​ 99% confidence interval for the population proportion is left parenthesis nothing comma nothing right parenthesis,. ​(Round to three decimal places as​ needed.)
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT