Which PROC FREQ step produced this table? Percent Table of Gender by Ques1 Gender Ques1 1 2 3 4 5 Total F 0.00 0.00 0.00 14.29 28.57 42.86 M 14.29 28.57 14.29 0.00 0.00 57.14 Total 1 14.29 2 28.57 1 14.29 1 14.29 2 28.57 7 100.00 Question 10 options: D. proc freq data=learn.survey; tables Gender*Ques1 / norow nocol; run; A. proc freq data=learn.survey; tables Gender*Ques1 / list; run; C. proc freq data=learn.survey; tables Gender*Ques1 / nocol; run; B. proc freq data=learn.survey; tables Gender*Ques1 / nofreq norow nocol; run;
The given table is as follows:
Percent Table of Gender by Ques1 Gender | |||
F | M | Total | |
1 | 0 | 14.29 | 14.29 |
2 | 0 | 28.57 | 28.57 |
3 | 0 | 14.29 | 14.29 |
4 | 14.29 | 0 | 14.29 |
5 | 28.57 | 0 | 28.57 |
Total | 42.86 | 57.15 | 100 |
In the above table, we have cell percentages only and no frequencies, no row and column percentages. Hence, nofreq norow nocol should have been used in PROC FREQ.
Correct Option B.) proc freq data=learn.survey; tables Gender*Ques1 / nofreq norow nocol; run;
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