How many different committees can be formed from 12 teachers and 33 students if the committee consists of 2 teachers and 3 students?
There are C(12,2) ways to select 2 teachers from 5 and C(33,3) ways to select 3 students from 33.
C(n,r) is the combination of n units taken r at time.
Using the multiplication counting principle, the number of different committees that can be formed is given by:
C(12,2)*C(33,3) =
=
=
=
Hence, 360096 committees can be formed from 12 teachers and 33 students if the committee consist of 2 teachers and 3 students?
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