About % of the area under the curve of the standard normal distribution is outside the interval Z = (-0.77,0.77) (or beyond 0.77 standard deviations of the mean). Please show your answer to 2 decimal places show on how to imnput on graphing calculator
Solution:
Cosider the standard normal variable z.
Area outside the interval Z = (-0.77,0.77)
= 1 - {Area between Z= -0.77 and Z = 0.77 }
= 1 - {P(-0.77 Z 0.77) }
Use graphing calculator to find {P(-0.77 Z 0.77)
Press 2nd and then press VARS
Go to normalcdf
normalcdf(-0.77,0.77,0,1)
So , to find the answer of given question , on graphing calculator
1 - normalcdf(-0.77 , 0.77 , 0 , 1)
= 0.441299892685
= 0.4413
= 44.13 %
Answer : 44.13 %
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