Question

The weights of bowling balls are normally distributed with mean
11.5 pounds and standard deviation 2.7 pounds. A sample of 36
bowling balls is selected. What is the probability that the average
weight of the sample is less than 11.27 pounds?

Write only a number as your answer. Round to 4 decimal places (for
example 0.0048). Do not write as a percentage.

**Please explain how to use Ti-84 Plus CE with
this**

Answer #1

P ( < 11.27) = P ( = P (Z < - ) [ where Z is a standard normal variable ]

= P (Z <= -0.51111) = P (Z< = - 0.51) = 0.30503 = 0.3050 [ Round to 4 decimal places]

Used standard normal table to get the Probability value.

Please let ma know if you have any doubts. Thanks!!

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