For a standard normal? distribution, determine the probabilities in parts a through d below.
a. Find ?P(z ? 1.53).
b. Find ?P(z ? ?1.25?).
c. Find P(?0.81 ? z ? 1.77?).
d. Find ?P(0.33 ? z ? 2.11?).
Solution:
Given that,
Using standard normla table
, a ) ?P(z ? 1.53).
To see the z value 0.1 in the column and 0.53 in the row of the
standard normal table the corresponding probability is
Probability =0.9370
b ) P(Z < - 1.25 )
To see the z value - 0.1 in the column and 0.25 in the row of the
standard normal table the corresponding probability is
Probability =0.1056
c ) P(?0.81 ? z ? 1.77?)
P ( z < 1.77 ) - P ( z < - 0.81 )
= 0.9616 - 0.2090
= 0.7526
Probability = 0.7526
d ) P(0.33 ? z ? 2.11 )
P ( z < 2.11 ) - P ( z < 0.33 )
= 0.9826 - 0.6293
= 0.3533
Probability = 0.3533
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