Question

(47) – (49): Lottery tickets numbered 1 to 27 are handed out at a fair. If one ticket number is randomly selected, find the probability of selecting:

47) an odd number.   A) 14/27   B) 13/27   C) 12/27   D) 11/27

48) a number divisible by 6.   A) 6/27   B) 5/27   C) 4/27   D) 3/27

49) an odd number or a number divisible by 6.   A) 17/27   B) 18/27   C) 19/27   D) 20/27

50) A family has two children. Assuming male children and female children are equally likely, find the probability that the family has at least one female child.

Answer 1

47) Number of odd numbers = 14

{1,3,5,7,9,11,13,15,17,19,21,23,25,27}

Total numbers on lottery ticket = 27

P(an odd number) = 14/27

48) Number of numbers divisible by 6 = 4

{6,12,18,24}

P(a number divisible by 6) = 4/27

49) P(odd number or divisible by 6) = P(odd number) + P(divisible by 6) - P(odd number and divisible by 6)

= 14/27 + 4/27 - 0

= 18/27

50) P(male child) = P(female child) = 0.5

P(at least one female child) = 1 - P(both male children)

= 1 - 0.5x0.5

= 0.75