Suppose certain coins have weights that are normally distributed with a mean of 5.629 g and a standard deviation of 0.056 g. A vending machine is configured to accept those coins with weights between 5.559 g and 5.699 g.
a. If 280 different coins are inserted into the vending machine, what is the expected number of rejected coins?
From normal distribution, we calculate the proportion of coins with a weight between 5.559 g and 5.699. We will use that proportion as a parameter of the binomial distribution.
We need to compute Pr (5.559 ≤ X ≤ 5.699). The corresponding z-values needed to be computed are:
Therefore, we get:
The proportion of coins that are accepted in the vending machine is 0.7887.
Therefore, the proportion of coins that are rejected in the vending machine is 1 - 0.7887 = 0.2113
Hence, the expected number of rejected coins is 0.2113 * 280 = 59.164 59 coins.
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