Question

Suppose babies born in a large hospital have a mean weight of 4090 grams, and a variance of 313,600. If 64 babies are sampled at random from the hospital, what is the probability that the mean weight of the sample babies would be greater than 4144 grams? Round your answer to four decimal places.

Answer 1

= 4090

n = 64

SE = /

= 560/

= 70

To find P( > 4144):

Z = (4144 - 4090)/70

= 0.7714

By Technology, Cumulative Area Under Standard Normal Curve = 0.7798

So,

P( > 4144):= 1 - 0.7798 = 0.2202

So,

Answer is:

0.2202