You conduct 82 Bernoulli trails with probability 0.829 of success. What is the probability that you will obtain exactly 36 successes? Round your answer to three decimal places. even if the third decimal place is a 0.
Solution:-
Let,
n= 82 Bernoulli trials were conducted with probability of success is (p=0.829)
Define
Xi : Bernoulli trials with probability p=0.829
Let
Y=Sum(Xi) .........i=1,2,3,4......,n.
Then
Y~Binomial (n=82 ,p=0.829) distribution
Then pmf of Y is given as
Now,
Question) What is probability that you will obtain exactly 36 successes?
----> i.e. we have to find P(Y=36) =?
Therefore,
The probability that you will obtain exactly 36 successes = P(Y=36) =0
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