A developer wants to know if the houses in two different neighborhoods were built at roughly the same time. She takes a random sample of six houses from each neighborhood and finds their ages from local records. The accompanying table shows the data for each sample (in years). Assume that the data come from a distribution that is Normally distributed. Complete parts a through c below.
1 | 2 |
66 | 52 |
61 | 37 |
47 | 57 |
48 | 47 |
68 | 54 |
46 | 53 |
Find a 95% confidence interval for the mean difference, muμ1minus−muμ2, in ages of houses in the two neighborhoods. (__,__)
(Round to two decimal places as needed.)
b) Is 0 within the confidence interval?
Yes
No
c) What does the confidence interval suggest about the null hypothesis that the mean difference is 0?
A.
Fail to rejectFail to reject
Upper H 0H0
since 0
isis
a plausible value for the true mean difference.
B.
RejectReject
Upper H 0H0
since 0
isis
a plausible value for the true mean difference.
C.
Fail to rejectFail to reject
Upper H 0H0
since 0
is notis not
a plausible value for the true mean difference.
D.
RejectReject Upper H 0H0 since 0 is not a plausible value for the true mean difference.
Neighborhood 1 | Neighborhood 2 | |
sample mean x = | 56.00 | 50.00 |
standard deviation s= | 10.139 | 7.155 |
sample size n= | 6 | 6 |
Pooled Std dev Sp=√((n1-1)s21+(n2-1)*s22)/(n1+n2-2)= | 8.77 | ||
Point estimate : x1-x2= | 6.0000 | ||
std. error se =Sp*√(1/n1+1/n2)= | 5.0662 |
point estimate of difference=x1-x2= | 6.000 | ||
for 95 % CI & 10 df value of t= | 2.228 | from excel: t.inv(0.975,10) | |
margin of error E=t*std error = | 11.2876 | ||
lower bound=mean difference-E= | -5.29 | ||
Upper bound=mean differnce +E= | 17.29 | ||
from above 95% confidence interval for population mean =(-5.29 , 17.29) |
b)
Yes
c)
A) Fail to reject Ho since 0 is a plausible value for the true mean difference.
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