Please show work so I understand how to solve thanks
A raffle has a grand prize of a Alaskan cruise valued at $12000
with a second prize of a Las Vegas getaway valued at $800. If each
ticket costs $4 and 9400 tickets are sold, what are the expected
winnings far a ticket buyer? Express to at least three
decimal place accuracy in dollar form (as opposed to
cents).
Answer: $
solution:
first price = $12000
second price = $800
total ticket sold = 9400
one ticket will get the grand prize so P(grand price ) = 1/9400,
one ticket will get the grand prize so, p(second prize) = 1/9400
payment for each ticket = $2
Probability of winning $12000 = 1/9400
probability of winning $800 = 1/9400
your expected value is = -4 + (1/9400 * 12000) + (1/9400 * 800) = -2.638$
2 nd method to solve this
total ticket 9400 @ $ 4
total money shelted out = 9400 * 4 = 37600
One ticket winning = 12000
one ticket winning = 800
Total value for all ticket for buyer = 12000 + 800 - 37600 = - 24800
average gain on each ticket will be = - 24800 / 9400 = - 2.638$
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