The following data show the brand, price ($), and the overall score for six stereo headphones that were tested by a certain magazine. The overall score is based on sound quality and effectiveness of ambient noise reduction. Scores range from 0 (lowest) to 100 (highest). The estimated regression equation for these data is ŷ = 25.465 + 0.305x, where x = price ($) and y = overall score.
Brand Price ($) Score
A 180 78
B 150 69
C 95 61
D 70 58
E 70 42
F 35 28
(a) Compute SST, SSR, and SSE. (Round your answers to three decimal places.)
SST =
SSR =
SSE =
(b) Compute the coefficient of determination r2. (Round your answer to three decimal places.)
r2 =
(For purposes of this exercise, consider a proportion large if it is at least 0.55.)
1. The least squares line did not provide a good fit as a large proportion of the variability in y has been explained by the least squares line.
2. The least squares line did not provide a good fit as a small proportion of the variability in y has been explained by the least squares line.
3. The least squares line provided a good fit as a large proportion of the variability in y has been explained by the least squares line.
4. The least squares line provided a good fit as a small proportion of the variability in y has been explained by the least squares line.
(c) What is the value of the sample correlation coefficient? (Round your answer to three decimal places.)
a)
ΣX | ΣY | Σ(x-x̅)² | Σ(y-ȳ)² | Σ(x-x̅)(y-ȳ) | |
total sum | 600.00 | 336.00 | 14950.00 | 1662.00 | 4565.00 |
mean | 100.00 | 56.00 | SSxx | SSyy | SSxy |
SSE= (SSxx * SSyy - SS²xy)/SSxx =
268.0719
SSR= S²xy/Sxx = 1393.9281
Ssyy= SST = 1662
b)
R² = 1-SSE/SST = 0.8387
3. The least squares line provided a good fit as a large proportion of the variability in y has been explained by the least squares line.
c)
SSE= (SSxx * SSyy - SS²xy)/SSxx =
268.0719
std error ,Se = √(SSE/(n-2)) =
8.1865
correlation coefficient , r = SSxy/√(SSx.SSy)
= 0.916
Please let me know in case of any doubt.
Thanks in advance!
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