A large collection of one-digit random numbers should have about 50% odd and 50% even digits\ because five of the ten digits are odd (1, 3, 5, 7, and 9) and five are even (0, 2, 4, 6, and 8).A. .Find the proportion of odd-numbered digits in the following lines from a random number table. Count carefully:
9 9 2 8 9 7 6 5 8 3 0 8 6 0 2
3 7 8 4 9 9 2 8 8 0 1 3 4 3 7
a. The given random number table consists of Answer ______ % odd-numbered digits. (Round to two decimal places as needed.)
b. Does the proportion found in part (a) represent p with caretp (the sample proportion) or p (the population proportion)? Answer __________proprortion.
Modifying Above p with caretp (the sample proportion)
C. Find the error in this estimate, the difference between p and p (or p-p). Error = Answer _____%
(Round to two decimal places as needed.)
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