A 95% confidence interval for a population mean is given as 32.2 < μ < 42.0. Round your answers to 1 decimal place.
(a) Calculate the sample mean. x =
(b) Calculate the margin of error. E =
Solution:
Given a 95% confidence interval for mean is 32.2 < μ < 42.0
We know , confidence interval for mean is given by
sample mean margin of error
So ,
Lower Limit = sample mean - margin of error
Upper Limit = sample mean + margin of error
Solving these two equations , we can say that
Sample mean = (Upper Limit + Lower Limit)/2
Margin of error = (Upper Limit - Lower Limit)/2
a)
Sample mean = (Upper Limit + Lower Limit)/2 = (42.0 + 32.2)/2 = 37.1
Sample mean = 37.1
b)
Margin of error = (Upper Limit - Lower Limit)/2 = (42.0 + 32.2)/2 = 4.9
Margin of error E = 4.9
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