A random sample of 30 male college students was selected, and their heights were measured. The heights (in inches) are given below.
73 | 66 | 68 | 70 | 69 | 69 |
69 | 66 | 68 | 70 | 72 | 74 |
73 | 71 | 71 | 72 | 69 | 68 |
66 | 73 | 74 | 72 | 68 | 71 |
67 | 73 | 66 | 73 | 69 | 72 |
(a) Complete the frequency distribution for the data. Make sure to enter your answers for the relative frequency as decimals, rounded to the nearest tenth.
Height | Frequency | Relative Frequency |
66 | ||
67 | ||
68 | ||
69 | ||
70 | ||
71 | ||
72 | ||
73 | ||
74 |
(c) Compute the (weighted) sample mean. Make sure to enter your
answer rounded to the nearest tenth.
(d) Interpret the sample mean obtained in question (c) in the
context of the problem.
a.
Height | Frequency | Relative Frequency |
66 | 4 | 4/30 = 13.33% |
67 | 1 | 1/30 = 3.33% |
68 | 4 | 4/30 = 13.33% |
69 | 5 | 5/30 = 16.67% |
70 | 2 | 2/30 = 6.67% |
71 | 3 | 3/30 = 10% |
72 | 4 | 4/30 = 13.33% |
73 | 5 | 5/30 = 16.67% |
74 | 2 | 2/30 = 6.67% |
b.
mean = (sum of height*freq) / n
= (66*4 + 67*1 + 68*4 + 69*5 + 70*2 + 71*3 + 72*4 + 73*5 + 74*2)/30
= 70.0667
c.
this shows that on average the height will be 70.0667 and since it is whole number it will be most probably 70 and second highest probability of 71
(please UPVOTE)
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