ANOVAb |
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Model |
Sum of Squares |
df |
Mean Square |
F |
Sig. |
|
1 |
Regression |
109,780 |
3 |
36,593 |
617,763 |
,030a |
Residual |
10,722 |
181 |
,059 |
|||
Total |
120,501 |
184 |
||||
a. Predictors: (Constant), F4, F2, F3 |
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b. Dependent Variable: F1 |
Coefficientsa |
||||||
Model |
Unstandardized Coefficients |
Standardized Coefficients |
t |
Sig. |
||
B |
Std. Error |
Beta |
||||
1 |
(Constant) |
,356 |
,105 |
3,373 |
,001 |
|
F2 |
-,269 |
,026 |
-,699 |
-2,997 |
,030 |
|
F3 |
,030 |
,028 |
,570 |
2,103 |
,021 |
|
F4 |
,859 |
,024 |
,989 |
1,112 |
,141 |
|
a. Dependent Variable: F1 |
a- Write down the hypothesis, p- value and your conclusion.
b- Can you predict satisfaction score by using any of the independent variables? If yes, what are these variables write down the hypothesis for each of the variable and give your conclusion.
c- What is the most important variable?
(a) The hypothesis being tested is:
H0: β1 = β2 = β3 = 0
H1: At least one βi ≠ 0
The p-value is 0.030.
Since the p-value (0.030) is less than the significance level (0.05), we can reject the null hypothesis.
Therefore, we can conclude that the model is significant.
(b) The hypothesis being tested is:
H0: β1 = 0
H1: β1 ≠ 0
The p-value is 0.030.
Since the p-value (0.030) is less than the significance level (0.05), we can reject the null hypothesis.
Therefore, we can conclude that the slope, F2, is significant.
The hypothesis being tested is:
H0: β2 = 0
H1: β2 ≠ 0
The p-value is 0.021.
Since the p-value (0.021) is less than the significance level (0.05), we can reject the null hypothesis.
Therefore, we can conclude that the slope, F3, is significant.
(c) F3
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