Question

Suppose Komla throws a die repeatedly until he gets a six. What is the probability

that he needs to throw more than 10 times to get a six, to 3 decimal places?

Answer 1

Answer :

Komla throws a die repeatedly until he gets a six.

i.e probability of getting six = 1 / 6 = 0.1667

then q = 1 - p

= 1 - 0.1667

= 0.8333

Here we need to find the probability that he needs to throw more than 10 times to get a six,

i.e P(X > 10) = 1 - P(X < 10) --------> (1)

Using geometric distribution function,

we will get P(X < 10) = 0.8654

Substitute this value in equation 1,

P(X > 10) = 1 - 0.8654

= 0.135

The probability that he needs to throw more than 10 times to get a six = 0.135