Question

What sample size is needed to give the desired margin of error with margin of error= +/-5 with 95% confidence, s=18.

The answer is n is greater than or equal to 50 but i dont know how to get there

Answer #1

**Answer:**

**We know that the formula for Margin of error
is:**

Here we have S = 18 and 95% confidence, so alpha = 0.05 ( level of significance ). And ME = 5

So,

Now as alpha = 0.05 then .... from normal table.

so,

squaring, we get

**n = 49.787136**

**n = 50 ...
rounded**

**Hence to get the ME = 5 the answer is n is greater than
or equal to 50**

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