What sample size is needed to give the desired margin of error with margin of error= +/-5 with 95% confidence, s=18.
The answer is n is greater than or equal to 50 but i dont know how to get there
Answer:
We know that the formula for Margin of error is:
Here we have S = 18 and 95% confidence, so alpha = 0.05 ( level of significance ). And ME = 5
So,
Now as alpha = 0.05 then .... from normal table.
so,
squaring, we get
n = 49.787136
n = 50 ... rounded
Hence to get the ME = 5 the answer is n is greater than or equal to 50
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