Question

THE FOLLOWING QUESTION NEEDS TO BE DONE THROUGH MINITAB PLEASE! IF STEPS COULD BE PROVIDED SO I UNDERSTAND WHAT IS GOING ON THANKS.

4.20 Characteristics of lead users. Refer to the Creativity and Innovation Management (February 2008) study of lead users of children’s computer games, Exercise 4.6 (p. 186). Recall that the researchers modeled lead-user rating (y, measured on a 5-point scale) as a function of gender (x₁ = 1 if female, 0 if male), age (x₂, years), degree of centrality (x₃, measured as the number of direct ties to other peers in the network), and betweenness centrality (x₄, measured as the number of shortest paths between peers). The least squares prediction equation was

ˆy=3.58+.01x1−.06x2−.01x3+.42x4.y^=3.58+.01x1−.06x2−.01x3+.42x4.

1. Compute the predicted lead-user rating of a 10-year-old female child with five direct ties to other peers in her social network and with two shortest paths between peers.

2. Compute an estimate for the mean lead-user rating of all 8-year-old male children with 10 direct ties to other peers and with four shortest paths between peers.

Answer 1

The least-squares prediction equation is:

y = 3.58 + 0.01x1 − 0.06x2 − 0.01x3 + 0.42x4

The predicted lead-user rating of a 10-year-old female child with five direct ties to other peers in her social network and with two shortest paths between peers is:

Put x1 = 1, x2 = 10, x3 = 5, x4 = 2 in the regression equation:

y = 3.58 + 0.01*1 − 0.06*10 − 0.01*5 + 0.42*2

y = 3.78

The mean lead-user rating of all 8-year-old male children with 10 direct ties to other peers and with four shortest paths between peers.

Put x1 = 0, x2 = 8, x3 = 10, x4 = 4 in the regression equation:

y = 3.58 + 0.01*0 − 0.06*8 − 0.01*10 + 0.42*4

y = 4.68