The amount of corn chips in a 16-ounce bag by the dispensing machine has a normal distribution with a mean of 16.5 ounces and a standard deviation of 0.2 ounce. What chip amount represents the top 13 percentile for the bag weight distribution?
Solution: We are given:
We are required to find the chip amount that represents the top 13 percentile for the bag weight distribution.
The top 13 percentile will have 87 percentile of values below it.
First, we have to find the z-score corresponding to area = 1 - 0.13=0.87. Using the standard normal table, we have:
Now using the z-score formula, we have:
Therefore, the chip amount that represents the top 13 percentile for the bag weight distribution is 16.73
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