Question

1) A sample of 143 households yielded an average income of $1500 per month with a standard deviation of $514. The researcher wants to test at the 10% level of significance that the average monthly income of all households is not greater than $1575. What is the alternative hypothesis of this test?

Select one:

a. Mean = $1575

b. Mean > $1575

c. Mean < $1575

d. Mean ≠ 1575

2) Last year a sample of 164 farmers had an average yield of 2,400 tomatoes with a standard deviation of 700. This year the average dropped to 1800 with a standard deviation of 500 when 131 farmers were sampled. A researcher wants to test at the 3% level of significance that the difference in the average yield of all farmers from one year to the next does not exceed 750. What is the value of the test statistic?

Select one:

a. -2.14

b. 49.31

c. -150

d. -0.125

3)A sample of 150 science students at a particular school found that 27% prefer Chemistry to Physics. The researcher wants to test at the 2% level of significance that less than 10% of all students prefer Chemistry to Physics. What is the H_a of this test?

Select one:

a. p = 0.1

b. p ≠ 0.1

c. p < 0.1

d. p > 0.1

4)The following contingency table was analysed and the results are shown below:

	MALE	FEMALE
GRADE A	20 (18.35)	11 (12.65)	31
GRADE B	8 *	6 (5.71)	14
GRADE C	1 (2.37)	3 (1.63)	**
	29	***	49

Note: expected counts below observed counts

Chi Sq = 0.15 + **** + 0.01 + 0.01 + 0.79 + 1.15 = 2.33

DF: ?? p value: ???

Determine the missing value '****' ?

Select one:

a. 0.22

b. 0.01

c. 2.72

d. 2.11

5)A sample of 150 science students at a particular school found that 27% prefer Chemistry to Physics. The researcher wants to test at the 9% level of significance that 30% of all students prefer Chemistry to Physics. What is the value of the test statistic of this test?

Select one:

a. -80.21

b. -0.80

c. -0.03

d. 0.03

Answer 1

Q.1) The researcher wants to test at the 10% level of significance that the average monthly income of all households is not greater than $1575. That means average monthly income of all household is less than or equal to $1575.

Therefore, the alternative hypothesis in this case is,

Mean > $1575

Q.2) From given information the test statistic is,

t = -2.14

The value of test statistic = -2.14

Q.3) From given information the alternative hypothesis (Ha) is,

Ha: p < 0.1

Q.4) let missing value is "X"

Chi-sq = 0.15 + X + 0.01+ 0.01+ 0.79 + 1.15 = 2.3

=> 2.11 + x = 2.33

=> X = 2.33 - 2.11

=> X = 0.22

Therefore, the missing value = 0.22

Q.5) The test statistic is,

The value of test statistic = -0.80