Question

A patient comes into the emergency room complaining about an adverse reaction to some medicine they took at home. They tell you that they keep 4 different medicines in the same pill bottle. From what they remember they had 12​ Percocet, 14​ Xanax, 16​ Adderall, and 15 Excedrin in the bottle before they took the pill that made them sick. What is the probability that they took a​ Percocet? (answer in​ percent) (Round to 2 Decimal​ Places) The patient now has a​ breakthrough, he remembers that he actually took two pills and not just one. The first one he took was a Percocet for his​ migraine, but he still​ can't remember what the second pill was. What is the probability that the second pill he took was a​ Xanax? (answer in​ percent)

Answer 1

12​ Percocet, 14​ Xanax, 16​ Adderall, and 15 Excedrin

1.

P(percocet) = no. of percocet pill / total no. of pills

= 12 / (12+14+16+15)

= 0.2105

= 21.05%

P(percocet) = 21.05%

2.

The first one he took was a Percocet

now in bottle the pills are :

11​ Percocet, 14​ Xanax, 16​ Adderall, and 15 Excedrin

P(2nd pill = xanax) = no. of xanax / total no. of pills

= 14 / (11+14+16+15)

= 0.25 = 25%

P(2nd pill = xanax) = 25%

P.S. (please upvote if you find the answer satisfactory)